32^2x=16(x-1)

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Solution for 32^2x=16(x-1) equation: 



32^2x=16(x-1)

We move all terms to the left:

32^2x-(16(x-1))=0



We calculate terms in parentheses: -(16(x-1)), so:

16(x-1)

We multiply parentheses

16x-16

Back to the equation:

-(16x-16)



We get rid of parentheses

32^2x-16x+16=0

We add all the numbers together, and all the variables

-16x+32^2x+16=0

We move all terms containing x to the left, all other terms to the right

-16x+32^2x=-16

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